if x = 3 is solution of equation 3x² +(k-1 ) x+9=0 then 15 is
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put value of 3 in the equation at place of x
3(9)+k-1(3)+9=0
27+3k-3+9=0
33=-3k
k=-11
Answered by
0
27+(k-1)3+9=0
36+3k-3=0
3k= -33
k= -11
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