Question

If x-3 is the factor of ax square +5x+12 find the value of a

Answer 1

Answer:

value of x

x-3=0

x=0+3

x=3

value of a

ax^2+5x+12

a(3)^2+5(3)+12

a×9+15+12

a×9+27

a×9=-27

a=-27÷9

a=-3

Hope it helps

Answer 2

Answer:

let p(x) = ax^2 + 5x +12

Given x-3 is a factor

•°• p(3) = 0

==> a×(3)^2 + 5×3 +12 = 0

==> 9a + 15 +12 = 0

==> 9a = -27

==> a = -27/9 = -3