if X=3 is the root of the quadratic equation x^2-2kx-6=0 then find the value of k
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Hola there..
According to the question,
x = 3
p(x) = x² - 2kx - 6
=> x² - 2kx - 6 = 0
=> (3)² - 2k(3) - 6 = 0
=> 9 - 6 - 6k = 0
=> 3 - 6k = 0
=> 6k = 3
=> k = 3/6
=> k = 1/2
Hope this helps....:)
According to the question,
x = 3
p(x) = x² - 2kx - 6
=> x² - 2kx - 6 = 0
=> (3)² - 2k(3) - 6 = 0
=> 9 - 6 - 6k = 0
=> 3 - 6k = 0
=> 6k = 3
=> k = 3/6
=> k = 1/2
Hope this helps....:)
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