if x=3 its one root of the quadric equation x×x -2kx-6=0 find the vslue of k
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Answered by
4
x×x-2kx-6=0
X=3
k=??
x^2-2kx-6=0
(3)^2-2k(3)-6=0
9-6k-6=0
3-6k=0
3=6k
3/6=k
k = 1/2
this is your answer......
X=3
k=??
x^2-2kx-6=0
(3)^2-2k(3)-6=0
9-6k-6=0
3-6k=0
3=6k
3/6=k
k = 1/2
this is your answer......
Answered by
3
x=3
3×3-2×3k-6=0
9-6k=6
-6k+9=6
-k+9=6/-6
-k=-1-9
k=10
3×3-2×3k-6=0
9-6k=6
-6k+9=6
-k+9=6/-6
-k=-1-9
k=10
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