Math, asked by himmu40, 1 year ago

if x^3+kx^2+mx+10=(x+1)(x-2)(x-5) then find the value of k and m. answer it step by step plz

Answers

Answered by arunbanuganesh090
6

Answer:

k= -6 and m=3

Step-by-step explanation:

x^3+kx^2+mx+10=(x+1)(x-2)(x-5)

                          =(x^2-2x+x-2)(x-5)

                          =(x^3-5x^2-2x^2+10x+x^2-5x-2x+10)

                          =(x^3-6x^2+3x+10)

x^3+kx^2+mx+10= x^3-6x^2+3x+10

           therefore k= -6 and m= 3

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