if x^3+kx^2+mx+10=(x+1)(x-2)(x-5) then find the value of k and m. answer it step by step plz
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Answer:
k= -6 and m=3
Step-by-step explanation:
x^3+kx^2+mx+10=(x+1)(x-2)(x-5)
=(x^2-2x+x-2)(x-5)
=(x^3-5x^2-2x^2+10x+x^2-5x-2x+10)
=(x^3-6x^2+3x+10)
x^3+kx^2+mx+10= x^3-6x^2+3x+10
therefore k= -6 and m= 3
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