Question

If x=3 one root of quadratic equation of x2- 2kx-6=0. Then find the value of k

Answer 1

Hi there!

Given,
x = 3 is root of Quadratic eqn. x² - 2kx - 6

Thus,

(3)² - 2k × 3 - 6 = 0

⇒ 9 - 6k - 6 = 0

⇒ 3 - 6k = 0

⇒ 6k = 3

⇒ k = 3/6 = 1/2

[ Thank you! for asking the question. ]
Hope it helps!

Answer 2

Solution :-

Given that x = 3 is one root of the quadratic equation x² - 2kx - 6 = 0

So, substituting x = 3 in the above equation.

⇒ (3)² - (2*k*3) - 6 = 0

⇒ 9 - 6k - 6 = 0

⇒ - 6k = 6 - 9

⇒ - 6k = - 3

⇒ k = 3/6

⇒ k = 1/2

So, the value of k is 1/2

Answer.