If x = 3 one root of the equation is
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1
(3)2-2k-6=0
9-2k-6=0
3=2k
k3/2
9-2k-6=0
3=2k
k3/2
Answered by
1
Given that x = 3
x^2 -2k -6 = 0
putting the value of x,
3^2 -2k = 6
9 - 2k = 6
-2k = 6-9
-2k = -3
2k = 3
k= 3/2
i hope this will help you
-by ABHAY
x^2 -2k -6 = 0
putting the value of x,
3^2 -2k = 6
9 - 2k = 6
-2k = 6-9
-2k = -3
2k = 3
k= 3/2
i hope this will help you
-by ABHAY
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