if x=3 one root of the xsq+2kx-6=0 find the value of k
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x^2 + 2kx - 6 = 0
put x=3.
3^2+2(3)k-6=0
9+6k-6=0
6k+3=0
k=-3/6 or k= -1/2
put x=3.
3^2+2(3)k-6=0
9+6k-6=0
6k+3=0
k=-3/6 or k= -1/2
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