Math, asked by Arbabkhan7173, 9 months ago

If x= 3+ root 8 , find the value of x^3 + 1/x^3

Answers

Answered by aakriti05
0

Step-by-step explanation:

x = 3+ √8

x = (3+√8)(3-√8) / (3-√8)

x = (9 -8) / (3-√8)

x = 1/ (3 -√8)

Or we can write 1/x = (3-√8)

Put the value and find out

x² +(1/x²) = x² + (1/x)²

So x² + 1/ x² = (3 +√8)² + (3 -√8)²

= 9+6√8+8 + 9–6√8+8

= 34. Ans.

Hope it helps MRK ME As BRAINLIEST

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