If x = 3 + root3 and xy = 6, then what is
the value (x + y)^2?
Answers
Answered by
1
Step-by-step explanation:
(x+y)²=x²+y²+2xy
=(3+root3)²+y²+2*6
=9+3+6root3+(6/3+root3)²+12
=12+6root3+36/12+6root3+12
=(12(12+6root3)+(6root3+12)(6root3)+36+12(12+6root3))/12+6root3
=(144+72root3+108+72root3+36+144+72root3)/12+6root3
=(432+216root3)/12+6root3
Answered by
0
Answer:
The answer of the above questionis 24+6 root 3
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