Math, asked by Shizukavuga6r9g, 1 year ago

If x = 3 + root8, find the value of x^2 + 1/x^2.

Answers

Answered by SDR
9
AGAIN 1/X=1/(3+√8)=(3-√8)/(3²-(√8)²)=3-√8
S0 1/X²=(3-√8)²
X²+1/X²=(3+√8)²+(3-√8)²=2(9+8)=34
Answered by vaishnavi150307
1

Answer:

34

Step-by-step explanation:

x=3+√8

=> 1/x=1/3+√8 × 3-√8/3-√8 = 3-√8/(3)^2-(√8)^2

=3-√8/9-8 = 3-√8/1 = 3-√8

Now, (x^2 + 1/x^2) = [(3+√8)^2 + (3-√8)^2]

=[(9+8+6√8) + (9+8-6√8)]

=(17+6√8 + 17-6√8)

=34

Hope It Helps!!

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