if x=3+![\sqrt[2]{2}](https://tex.z-dn.net/?f=+%5Csqrt%5B2%5D%7B2%7D+ "\sqrt[2]{2}")
find the value of 
+1/
Answers
Answered by
1
Pls check the ans.
Hope it helps.
Hope it helps.
Attachments:
brainly107:
2 can be written as root 2 raised to power 2
By splitting the value of x it became an identity (a + b ) ^2 = a^2 + b^2 + 2ab
Similar questions