If x+3,x+1 andx-7 are in AP find the value of x
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HEY MATE HERE IS YOUR ANSWER
a=x+3
n=3
d=x+1-(x+3)
d=-2
an=x-7
an=a+(n-1)d
x-7=x+3+(3-1)-2
x-7=x+3-4
-6=0
Hence we can say that they are not in AP
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a=x+3
n=3
d=x+1-(x+3)
d=-2
an=x-7
an=a+(n-1)d
x-7=x+3+(3-1)-2
x-7=x+3-4
-6=0
Hence we can say that they are not in AP
HOPE IT HELPS YOU
FOLLOW ME FOR ANY OTHER QUESTIONS
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