if x^3 +x^2-2x-3=(x-2) (x2+ax+b)+5,then
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a = 3 , b = 4 -------------- Ans
Step-by-step explanation:
x^3 + x^2 - 2x - 3 -------- where ^ represents raise to the power.
=> x^3 + x^2 - 2x -3 - 5 = (x-2)(x^2+ax+b)
=> x^3 + x^2 - 2x - 8 = (x-2)(x^2+ax+b)
At x = 2, x^3 + x^2 - 2x - 8 = 0
=> (x - 2) is a factor of x^3 + x^2 - 2x - 8;
Dividing x^3 + x^2 - 2x - 8 by (x-2), we get ---
(x-2)(x^2+3x+4) = (x-2)(x^2+ax+b)
=> x^2+3x+4 = x^2+ax+
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