Question

if(x+3)(x-2) + (2x - 5) + 8z is added to (x-4)(x-5)+ 3x , then the result is
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Answer 1

Answer:

9x-13+8z

Step-by-step explanation:

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Answer 2

$\sf{\left(\left(x+3\right)\left(x-2\right)+\left(2x-5\right)+8z\right)+\left(\left(x-4\right)\left(x-5\right)+3x\right)}$

$\sf{=\left(x+3\right)\left(x-2\right)+2x-5+8z+\left(x-4\right)\left(x-5\right)+3x}$

$\sf{=x^2+x-6+2x-5+8z+\left(x-4\right)\left(x-5\right)+3x}$

$\sf{=x^2+x-6+2x-5+8z+x^2-9x+20+3x}$

$\sf{=x^2+x^2+x+2x-9x+3x+8z-6-5+20}$

$\sf{=2x^2+x+2x-9x+3x+8z-6-5+20}$

$\sf{=2x^2-3x+8z-6-5+20}$

$\bf{=2x^2-3x+8z+9}$