Question

If x^3+x^2+x+1 upon x^3-x^2+x+1 = x^2+x+1 upon x^2+x+1, then the number of real value of x satisfying are​

Answer 1

Answer:

Step-by-step explanation:

(x³+x²+x+1)/(x³-x²+x+1) = (x²+x+1)/(x²+x+1)

x³+x²+x+1 = x³-x²+x+1

rearranging terms we get

2x² = 0

x = 0