Question

if x = 3, y = 1, z = -4 find the value of x3 + y3 +z3 -3xyz​

Answer 1

Answer:

3^3+1^3+(-4^3)-3×(1)×(3)×(-4)

27+1-64+36

64-64=0

Answer 2

Answer:

x³+y³+z³-3xyz = 0

Step-by-step explanation:

GIVEN VALUE,

x = 3

y = 1

z = -4

SO,

SUBSTITUTING IT INTO THE GIVEN EQUATION,

WE GET,

x³+y³+z³-3xyz

(3)³+(1)³+(-4)³ -3(3)(1)(-4)

27+1-64+36

64-64

0

SO,

x³+y³+z³-3xyz = 0

I HOPE YOU UNDERSTOOD THE QUESTION!!!