if x,3,y,12 are in continued proportion then find x and y. please answer me tomorrow is my exam
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3
xy=9 and 3*12=y^2
xy=9 and y^2=36
xy=9 and y=6
x=9/6=3/2
xy=9 and y^2=36
xy=9 and y=6
x=9/6=3/2
Answered by
1
Answer:3/2
Step-by-step explanation:take x/3,3/y,y/12
Now, 3/y=y/12
y²=12*3
y² =36
y=6
Take another proportion
x/3=3/y
xy= 9
Take y as 6
x(6)=9
x=9/6
x=3/2
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