Math, asked by tiyasamalakar46, 2 days ago

If x=3 . y=-2 and z= -5 Find the value of xyz(x+y+z)

Answers

Answered by chakrabortyshivam44
1

Answer:

Given, Values of x= 3, y= -2 and z = -5

xyz(x+y+z)

= 3*(-2)*(-5)[3+(-2)+(-5)]

According to BODMAS,

Function of bracket comes first

= 3*(-2)*(-5)[3-2-5]

= 3*(-2)*(-5)[-4]

= 30(-4)

= -120

The value of xyz(x+y+z) is -120

Step-by-step explanation:

Hope this helps you

Answered by nb69119
0

Answer:

xyz(X+y+z)

Step-by-step explanation:

3 x (-2) x (-5) [ 3+(-2)+(-5)]

30 x [ -4 ]

Ans = -120

thanks

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