if x=3,y=-2 is solution of linear equation 3x-ky=1,then find the value of k
Answers
Answered by
27
3x-ky=1
3X3 - kX-2=1
9-(-2k)=1
9+2k=1
2k=1-9
2k = -8
k = -8/2
k=-4
3X3 - kX-2=1
9-(-2k)=1
9+2k=1
2k=1-9
2k = -8
k = -8/2
k=-4
Answered by
1
The value of k is -4
Given:
x = 3, y = -2
3x - ky = 1 is a linear equation
To find:
The value of k
Solution:
Given x = 3, y = -2 are solution of given equation 3x - ky = 1
Which means for given values of x and y the given equation will be satisfied
Now substitute x and y values in given equation to find the value of k
⇒ 3(3) - k(-2) = 1
⇒ 9 + 2k = 1
⇒ 2k = -8
⇒ k = -4
Therefore, the value of k = -4
#SPJ2
Similar questions