Question

if x=3 y=2 then the value of (x-y) (x²+xy+y²) is​

Answer 1

Answer:

(x-y)(x^2+xy+y^2)=(x^3-y^3)

now putting the values of x & y

(3)^3-(2)^3

2×2×2-3×3×3

8-27=-19

Answer 2

If x = 3 , y = 2 then the value (x - y) (x² + xy + y²) is 19

Given :

The expression (x - y) (x² + xy + y²)

To find :

The value of the expression for x = 3 , y = 2

Formula :

x³ - y³ = (x - y) (x² + xy + y²)

Solution :

Step 1 of 2 :

Simplify the given expression

The given expression is

(x - y) (x² + xy + y²)

Thus we have

(x - y) (x² + xy + y²)

= x³ - y³

Step 2 of 2 :

Find the value of the expression for x = 3 , y = 2

Putting x = 3 , y = 2 we get

The given expression

= (x - y) (x² + xy + y²)

= x³ - y³

= 3³ - 2³

= 27 - 8

= 19

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