Math, asked by maheshmahesh, 10 months ago

if X + 3 Y = 26 and xy = 26 find the value of 8 x cube + 27


bijit333: wrong question

Answers

Answered by waqarsd
1

Step-by-step explanation:

2x + 3y = 26 \\  \\ xy = 26 \\  \\ cobs \\  \\  {(2x + 3y)}^{3}  =  {26}^{3}  \\  \\ 8 {x}^{3}  + 27 {y}^{3}  + 18xy(2x + 3y) =  {26}^{3}  \\  \\  8 {x}^{3}  + 27 {y}^{3}  + 18 \times 26(26) =  {26}^{3}  \\  \\  8 {x}^{3}  + 27 {y}^{3} =  {26}^{2} (26 - 18) \\  \\  8 {x}^{3}  + 27 {y}^{3} = 8 \times  {26}^{2}  \\  \\  8 {x}^{3}  + 27 {y}^{3} = 5408 \\  \\ we \: have \\  \\  {(x + y)}^{3}  =  {x}^{3}  +  {y}^{3}  + 3xy(x + y) \\  \\

hope it helps

Answered by gujjarankit
2

Answer:

hey mate here is ur answer hope u find it helpful

Attachments:
Similar questions