if x^3+y^3=1957 and (x+y )(x+1)(y+1)=2014 find x +y
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Answer:
x+y=19.
Step-by-step explanation:
x³+y³=1957
By the formula, (a³+b³)=(a+b)*(a²+b²+ab)
Thus, (x+y)(x²+y²+xy)=1957,
1957=19*103,
2014=19*106,
So, both have a common factor 19.
Also, (x+y) is a common factor
Hence, (x+y)=19.
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