if x^3+y^3=8,X^2+y^2=4,x+y=?
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Answer:
Here, x+y=2.
Step-by-step explanation:
Here, As per our given question,
=x^3+y^3=8
Now, =x^2+y^2=4
So, As it is decreasing in a proportional order,
=x+y=2 [As, 2 becomes 4 when squared and increases to 8 when we do cube of it].
Thank you.
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