Question

if (x^3+y^3/x^2)^-1 -(x^3+y^3/xy)^-1 +(x^3+y^3/xy^2)^-1 = 1/3 find the value of (x+y)​

Answer 1

Answer:

please find the attachment

Answer 2

Step-by-step explanation:

if (x^3+y^3/x^2)^-1 -(x^3+y^3/xy)^-1 +(x^3+y^3/xy^2)^-1 = 1/3 find the value of (x+y)