Question

if x^3001+71 is divided by x+1 then the remainder is

Answer 1

Hope this will help you.
x + 1 = 0
so, x = -1

=> x^3001 + 71
=> (-1)^3001+71
=> -1 + 71
=> 70 is the answer.

Answer 2

Answer:

The remainder of the polynomial function $x^{3001} + 71$ is 70

Step-by-step explanation:

Given: The polynomial function $x^{3001} + 71$ divided by x+1

To find: The remainder for the polynomial function

Solution:

Given that the polynomial function $x^{3001} + 71$ divided by x+1

According to the remainder theorem, f(x) is divided by a linear polynomial(x-a)

Let f(x) = $x^{3001} + 71$

Remainder theorem:

Remainder Theorem is a method for dividing polynomials according to Euclidean geometry.

This theorem states that when a polynomial P(x) is divided by a factor

(x - a), which isn't really an element of the polynomial, a smaller polynomial is produced along with a remainder.

Here,

x-a = x+1

Therefore x = -1

Sub x= -1 in the function

f(x) = $x^{3001} + 71$

f(-1) = $(-)^{3001} + 71$

$f(-1) = -1 +71$

$f(-1) = 70$

Remainder =70

Final answer:

The remainder of the polynomial function $x^{3001} + 71$ is 70

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