Question

If x=3a + 2b - c, y=a -4b + 4c , z= 2a + 3b + 5c, find x+y+z​

Answer 1

Step-by-step explanation:

3a+2b-c+a-4b+4c+2a+3b+5c

3a+b-1c+1a-4b+4c+2a+3b+5c

(3a+1a+2a)+(2b+[-4b]+3b)+([-C]+4c+5c)

6a+1b+8c

6a+b+8c Ans

Answer 2

Step-by-step explanation:

$x=3a + 2b - c \\ y=a -4b + 4c \\ z= 2a + 3b + 5c \\ \\ x + y + z \\ =(3a + 2b - c )+ (a -4b + 4c) + (2a + 3b + 5c) \\ =3a + 2b - c + a -4b + 4c + 2a + 3b + 5c \\ = 6a + b + 8c$

Hope it will help