Question

if x=3a3+3a+5a2+8,y=3a2+5a3-4a+1 and z=7-7a+6a3-4a2, then find x+y-z

Answer 1

Answer:

as x ,y and z are given

now we have to find x+y-z ?

so put the value of x, y and z

x+y-z= (3a3+3a+5a2+8)+(3a2+5a3-4a+1)-(7-7a+6a3-4a2)

=(8a3+8a2-a+9)-7+7a-6a3+4a2

=2a3+12a2+6a+2

Answer 2

I don't know the answer