Question

if X =-3i +4j + 2 k ,y =3i-2j+8k and z= 2i+4j-k then find the direction cosine of 2x-y+3z..​

Answer 1

Answer:

to find the direction cosine of 2x-y+3z

we have a formula = a^2/root x^2+y^2+z^2

here a^2=2x-y+3z and X, Y , Z are given .

put these value in the formula

cos a=(2x-y+3z)^2/root (-3i+4+2)^2+(3i-2j+8k)^2+(2x-y+3z)^2

solve it and get ur required answer

hope it helps.

any doubts u can ask me anytime ..

:-)

Answer 2

Answer:

answer in the attachment above

hope it's helpful