If x=3is one root of quadratic equation x-2kx-6=0then find k
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4
p(x) = x² - 2kx - 6 = 0
p(3) = 3² - 6k - 6 = 0
⇒ 9 - 6k - 6 = 0
⇒ 3 = 6k
⇒ k = 1/2
p(3) = 3² - 6k - 6 = 0
⇒ 9 - 6k - 6 = 0
⇒ 3 = 6k
⇒ k = 1/2
rahul1279:
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Answered by
9
If ur question is : x - 2kx - 6
3 - 6k - 6 = 0
-6 k - 3 = 0
k = - 1/2
_____________
If ur question is :- x² - 2kx - 6
then,
9 - 6k - 6 = 0
-6k + 3 = 0
k = 1/2
3 - 6k - 6 = 0
-6 k - 3 = 0
k = - 1/2
_____________
If ur question is :- x² - 2kx - 6
then,
9 - 6k - 6 = 0
-6k + 3 = 0
k = 1/2
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