Question

if x=3is one root of the quadratic equation x2-2kx-6=0then find k

Answer 1

here is your answer...
hope this helps you...

Answer 2

$hey \: mate \: here \: is \: your \: answer...$

${x}^{2} - 2kx - 6 = 0$
$\: \: on \: putting \: x = 3$
$(3) {}^{2} - 2k(3) - 6 = 0$
$9 - 6k - 6 = 0$
$3 - 6k = 0$
$- 6k = - 3$
$6k = 3$
$k = \frac{3}{6}$

$k = \frac{1}{2}$

$the \: value \: of \: k \: is \: \frac{1}{2}$




$hope \: it \: helps.....$