If x=3is one root of the square of x2-2kx -6=0 find the value of k
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put valu of x 3 in eq and solve
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3 sq - 2k×3-6
9-6k-6=0
6k=9-3
6k=3
k=3/6
k=1/2
9-6k-6=0
6k=9-3
6k=3
k=3/6
k=1/2
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