if x=3k+2 and y=2k-1 is a solution of equation 4x+3y+1=0 find the value of k
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x=3k+2 and y=2k-1
4x+3y+1=0
4(3k+2)+3(2k-1)+1=0
12k+8+6k-3+1=0
18k+6=0
18k=-6
k=-1/3
hope this helps you
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4x+3y+1=0
4(3k+2)+3(2k-1)+1=0
12k+8+6k-3+1=0
18k+6=0
18k=-6
k=-1/3
hope this helps you
please do mark as brainliest
dilnawaj:
nice answer
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