if x=3k+2 and y=2k-1 is a solution of the quation 4x-3y+1 =0 find the value of k
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Hope it helps
x=3k+2, y=2k-1
4x-3y+1=0
Putting the value of x and y
4(3k+2)-3(2k-1)+1=0
12k+8-6k+3+1=0
6k+12=0
6k=-12
k= -12/6
k= -2
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Hope it helps
x=3k+2, y=2k-1
4x-3y+1=0
Putting the value of x and y
4(3k+2)-3(2k-1)+1=0
12k+8-6k+3+1=0
6k+12=0
6k=-12
k= -12/6
k= -2
plz mark me as brainliest
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