if x=3k+2and y=2k-1 is a solution of a equation 4x-3y+1=0 find the value of k
Answers
Answered by
15
hey here is ur answer
4(3k+2)-3(2k)=-1
12k+8 -6k=-1
6k=-8-1
k=--9/6
k=-3/2
I hope this helps u
4(3k+2)-3(2k)=-1
12k+8 -6k=-1
6k=-8-1
k=--9/6
k=-3/2
I hope this helps u
khanaman287915:
wrong answer
Answered by
38
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x = 3k + 2 ------------ [ 1 ]
y = 2k - 1 ------------ [ 2 ]
.
Submit [ 1 ] and [ 2 ] into 4x - 3y + 1 = 0:
4x - 3y + 1 = 0
4(3k + 2) - 3(2k - 1) + 1 = 0
12k + 8 - 6k + 3 + 1 = 0
6k + 12 = 0
6k = -12
k = -2
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Answer: k = -2
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