Math, asked by khanaman287915, 1 year ago

if x=3k+2and y=2k-1 is a solution of a equation 4x-3y+1=0 find the value of k

Answers

Answered by khyathis
15
hey here is ur answer

4(3k+2)-3(2k)=-1
12k+8 -6k=-1
6k=-8-1
k=--9/6
k=-3/2

I hope this helps u

khanaman287915: wrong answer
Answered by TooFree
38

 \textbf {Hey there, here is the solution.}

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x = 3k + 2 ------------ [ 1 ]

y = 2k - 1 ------------ [ 2 ]

.

Submit [ 1 ] and [ 2 ] into 4x - 3y + 1 = 0:

4x - 3y + 1 = 0

4(3k + 2) - 3(2k - 1) + 1 = 0

12k + 8 - 6k + 3 + 1 = 0

6k + 12 = 0

6k = -12

k = -2

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Answer: k = -2

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 \textbf {Cheers}


khanaman287915: thanx
TooFree: You are welcome :)
khanaman287915: send ur pic
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