Question

if x=3k+2and y=2k-1 is a solution of a equation 4x-3y+1=0 find the value of k

Answer 1

Answer:

if x=3k+2and y=2k-1 is a solution of a equation 4x-3y+1=0  then the value of k is -2

Step-by-step explanation:

Given :

We are given that if the value of

• x = 3k +2
• y = 2k -1

satisfies the equation 4x -3y + 1 =0

To Find:

We have to find the value of k

Solution :

In the question we are given the values of x = 3k + 2 and y = 2k - 1

which satisfies the equation

4x - 3y + 1 =0

Now substitute the values of x and y in the equation

4(3k + 2) - 3(2k - 1) + 1 = 0

12k + 8 - 6k + 3 + 1 = 0

12k - 6k + 8 + 3 + 1 = 0

6k + 12 = 0

6k = -12

k = -2

hence we have calculated the value of k  = -2

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Answer 2

Answer:

-2 is the required value of k

Step-by-step explanation:

Explanation:

Given that, x = 3k + 2 and y = 2k - 1 is a solution of a equation 4x - 3y + 1 = 0.

So, according to the question we need to find out the value of k.

Therefore, from the question we have,

x = 3k + 2  and

y = 2k - 1.

Let 4x - 3y + 1 = 0 .............(i)

Now, put the value of x and y in equation (i) we get,

⇒ 4x - 3y + 1 = 0

⇒ 4 (3k + 2) - 3 (2k - 1) + 1 = 0

⇒ 12 k + 8 - 6k + 3 + 1 = 0

⇒ (12 k - 6k ) + (8 + 3 + 1) = 0

⇒ 6 k + 12 = 0

⇒6k = -12

⇒k = $\frac{-12}{6}$ = -2

Final answer:

Hence, the value of k is -2.

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