If x=3k+2and y=2k-1 is a solution of the equation 4x-3y+1=0,find the value of k
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Answered by
3
4x-3y+1=0
4(3k+2)-3(2k-1)+1=0
12k+8-6k+3+1=0
6k+12=0
6k=-12
k=-2
4(3k+2)-3(2k-1)+1=0
12k+8-6k+3+1=0
6k+12=0
6k=-12
k=-2
Answered by
6
4x-3y+1=0
here x =3k+2
y =2k-1
4(3k+2)-3(2k-1)+1=0
12k+8-6k+3+1=0
6k=-12
k=-2
here x =3k+2
y =2k-1
4(3k+2)-3(2k-1)+1=0
12k+8-6k+3+1=0
6k=-12
k=-2
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