Question

 If x= 3sec²θ - 1 and y = 3 tan²θ - 2 where θ is an acute angle, then the value of x-y is​

Answer 1

Answer:

hiii.... Ashish here Ur answer I hope this is helpful for you

Answer 2

Answer:

according to question :

x - y :

3sec^2theta - 3tan^2theta

taking 3 common,

3 (sec^2theta + tan^2theta)

now, we know the identity :

sec^2 theta = 1 + tan^2 theta

= 3 (1 + tan^2theta + tan^2theta)

= 3 ( 1 + 2tan^2theta)

now, place the value of any acute angle in the above equation,

you'll get your answer......

hope it helps:)