Math, asked by ReevanLobo, 11 months ago

if x =3sec2 A-1, y=tan^2 A -2 then x -3y is equal to -
a)3. b)4. c)8. d)5.

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Answers

Answered by rishu6845
6

Answer:

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Answered by sonabrainly
2

Answer:

Step-by-step explanation:

it is given that x = 3sec^2 a   and y = tan^2a - 2

then x-3y = ?

3sec^2a - 1 - 3tan^a + 6

3sec^2a - 3tan^2a + 6 - 1

taking 3 common

3(sec^2a - tan^2a) + 5

by the formula we know that

1 + tan^2 theta = sec^2 theta

from that

sec^2 theta - tan^2 theta = 1

3(1) + 5

x -  3y = 8

option c is the correct answer

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