if x =3sec2 A-1, y=tan^2 A -2 then x -3y is equal to -
a)3. b)4. c)8. d)5.
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6
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Step-by-step explanation:
it is given that x = 3sec^2 a and y = tan^2a - 2
then x-3y = ?
3sec^2a - 1 - 3tan^a + 6
3sec^2a - 3tan^2a + 6 - 1
taking 3 common
3(sec^2a - tan^2a) + 5
by the formula we know that
1 + tan^2 theta = sec^2 theta
from that
sec^2 theta - tan^2 theta = 1
3(1) + 5
x - 3y = 8
option c is the correct answer
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