If x=3sec2theta and y=tan2theta , find the value of x-3y.
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Answer:
x-3y=3sec2θ-3tan2θ
=3(sec2θ-tan2θ)
=3(1/cos2θ-sin2θ/cos2θ)
=3(1-sin2θ)/cos2θ
Explanation:
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