Question

If x=3sine and y = 4 cos then find the value of √16x² +9y2​

Answer 1

Step-by-step explanation:

x^2=9sin^2@

y^2=16cos^2@

√16*9sin^2@+9*16cos^@

√16*9(sin^2@+cos^2@)

√16*9=4*3=12

Answer 2

Answer:

x=3sinu and y=4cosu

Then 16x²+9y²=16(3sinu)²+9(4cosu)²

=16×9sin²u+9×16cos²u

=144(sin²u+cos²u)

=144(1)=144