If x = 3sinX + 4cosX and Y =3cosX -4sinX prove that x²+ y²=25.
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Step-by-step explanation:
Given equation
X=3 sinx+4cosx
Y=3cosx-4sinx
RHS=x^2+y^2
=(3sinx+4cosx)^2+(3cosx-4sinx)^2
=9sin^2 x+16cos^2 x+9cos ^2x-16sin^2 x =9sin^2x+9cos^2 x+16cos^2 x-16sin^2 x
=9(sin^2x+cos ^2 x)+16(cos^2 x- sin^2x)
=9+16
=25
=RHS
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