if X=3x²-8-7x, Y=x²+8x-3 and Z=-3x-5x²+2 find X+Y+Z
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Answered by
1
Answer:
a)A+B-C. =(3x²-7x-8 )+(x²+8x-3)-(-5x²-3x + 2). =3x²-7x-8+x²+8x-3+ 5x²+3x-2. =9x²+4x-13. b)A-B-C.
Answered by
3
Answer:
-x²-2x-9
Step-by-step explanation:
3x²-8-7x + x²+8x-3-3x-5x²+2
3x²+x²-5x²-7x+8x-3x-8-3+2
-x²-2x-9
Therefore, x+y+z= (-x²-2x-9)
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