If x + 3y = 16 is the perpendicular bisector of AB and A(5, 7), then B =
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Answer:
B is the image of A w. r. t line
Let B=(h, K)
h-5/1=k-7/3=-2(5+21-16)/1+9
h-5/1=k-7/3=-2
h=3,k=1
B=(3,1)
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Answer is (3,1)
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