if x+3y=5and xy=3,find x2+9y2
Answers
Answered by
4
(x+3)²=x²+9y²+2(x)(3y)=x²+9y²+6xy=5²put the value of xyx²+9y²+6(3)=5²x²+9y²+18=25x²+9y²=25-18=7
Answered by
10
Hey friend ☺ here is your answer _____________________________
As we know the identity of
(a + b)^2 = a^2 + b^2 + 2ab
(x + 3y)^2 = (x)^2 + (3y)^2 + 6xy
5^2 = x^2 + 9y^2 + 6 × 3
25 - 18 = x^2 + 9y^2
x^2 + 9y^2 = 7
Hope this helps you.
As we know the identity of
(a + b)^2 = a^2 + b^2 + 2ab
(x + 3y)^2 = (x)^2 + (3y)^2 + 6xy
5^2 = x^2 + 9y^2 + 6 × 3
25 - 18 = x^2 + 9y^2
x^2 + 9y^2 = 7
Hope this helps you.
Similar questions