If x = 3y = 5z; find (x-y+z):(x+y-z):(x-y-z) ?
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Answered by
1
Answer:
13:17:7
Step-by-step explanation:
Let x = 3y = 5z = 15k.
=> x = 15k & 3y = 15k & 5z = 15k
=> x = 15k & y = 5k & z = 3k
Therefore,
=> (x-y+z):(x+y-z):(x-y-z)
=> (15k-5k+3k) : (15k+5k-3k) : (15k-5k-3k)
=> (13k) : (17k) : (7k)
=> 13 : 17 : 7
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Answer:
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