Question

if x-4=12/x then the value of x is​

Answer 1

Answer:

x-4 = I2/x

x(x-4)=12

x^2-4x=12

x^2-4x-12=0

(x-6) (x +2)=0

x=6,x=-2

Value of x = 6,-2

Answer 2

As per the data given in the above question.

We have to find the value of x

Given,

$x-4= \frac{12}{x}$

Step-by-step explanation:

$x-4= \frac{12}{x}$

Cross - multiply the both terms ,

$x(x - 4) = 12$

Multiply the x by (x-4),

${x}^{2} - 4x = 12$

${x}^{2} - 4x - 12 = 0 \: \: \: \: \: \: ...(1)$

Solve the above equation by splitting method,

Factorization of Quadratic polynomials of the form

x² + bx + c.

(i) In order to factorize x² + bx + c we have to find numbers p and q such that p + q = b and pq = c.

(ii) After finding p and q, we split the middle term in the quadratic as px + qx and get desired factors by grouping the terms.

Now, factorize values

$-12 = -6 × 2 \\ </p><p>-4= -6+2$

We have to put in the equation (1)

${x}^{2} - 6x + 2x - 12 = 0$

$({x}^{2} - 6x) + (2x - 12) = 0$

Take out common x from 1st terms and 2 from 2nd term

$x(x - 6) + 2(x - 2) = 0$

$(x - 6)(x + 2) = 0$

$so \: \: x - 6 = 0 \\ x + 2 = 0$

$x = 6 \: and \: - 2$

Project code# SPJ2