If X^4 =16 and y^2 = 36 then the maximum possible value for x-y?
Answers
Answered by
1
Answer:8
Step-by-step explanation:
x⁴=16=>x=+2 or -2
y²=36=> y= +6 or -6
maximum value of x-y=2-(-6)=8
Answered by
1
Answer:
x = 2 and y = 6 hence x - y = 2 - 6
= -4
Step-by-step explanation:
angleranip6k6rd:
Wrong
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