Math, asked by angleranip6k6rd, 11 months ago

If X^4 =16 and y^2 = 36 then the maximum possible value for x-y?

Answers

Answered by Gautam22121998
1

Answer:8

Step-by-step explanation:

x⁴=16=>x=+2 or -2

y²=36=> y= +6 or -6

maximum value of x-y=2-(-6)=8

Answered by bhavya1810
1

Answer:

x = 2 and y = 6 hence x - y = 2 - 6

                                     = -4

Step-by-step explanation:


angleranip6k6rd: Wrong
bhavya1810: sorry u can report it
angleranip6k6rd: Ok
Similar questions