Math, asked by angleranip6k6rd, 1 year ago

If X^4 =16 and y^2 = 36 then the maximum possible value for x-y?

Answers

Answered by Gautam22121998

1

Answer:8

Step-by-step explanation:

x⁴=16=>x=+2 or -2

y²=36=> y= +6 or -6

maximum value of x-y=2-(-6)=8

Answered by bhavya1810

1

Answer:

x = 2 and y = 6 hence x - y = 2 - 6

= -4

Step-by-step explanation:

angleranip6k6rd: Wrong

bhavya1810: sorry u can report it

angleranip6k6rd: Ok

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