If x = 4/2 is a root of the polynomial f (x) = 6x³ - 11x² + kx - 20, find the value of k.
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Answered by
5
On putting the value of root of a polynomial into that polynomial we get 0
so, 6(4/3)^3-11(4/3)^2+k4/3-20=0
→128/9-176/9+k4/3 -20=0
→-48/9+k4/3 -20=0
→-16/3+k4/3 -20=0
→(4k-16)/3=20
→4k-16=60
→4k=76
→k=19
Blue14:
Dude I think that is 4/3
Not 4/2
It's ok I'll adjust
Oh k thanks
hmm
Answered by
1
Step-by-step explanation:
f (x) =6 (8)-11 (4)+2k-20=0
48-44-20+2k=0
2k=16
k=8
what is the step of root
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