Math, asked by Priyanvi, 1 year ago

if x=4-√3 and y=1 by x find the value of (x+y) cube

Answers

Answered by mantasakasmani
3
X = 4 - √3 = 4 - 1.73 = 2.27

y = 1

(X+y)^3

(X+y)^2 ( X+y)

x^2+2xy + y^2 ( X+ y)

(2.27)^2 + 2(2.27)(1) + (1)^2 ( 2.27 + 1)

5.15 + 4.54 + 1( 3.27)

5.15+ 4.54 + 3.27

12.96

this is your answer....

hope it helps you ☺..








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