if x=4-√3 and y=1 by x find the value of (x+y) cube
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X = 4 - √3 = 4 - 1.73 = 2.27
y = 1
(X+y)^3
(X+y)^2 ( X+y)
x^2+2xy + y^2 ( X+ y)
(2.27)^2 + 2(2.27)(1) + (1)^2 ( 2.27 + 1)
5.15 + 4.54 + 1( 3.27)
5.15+ 4.54 + 3.27
12.96
this is your answer....
hope it helps you ☺..
y = 1
(X+y)^3
(X+y)^2 ( X+y)
x^2+2xy + y^2 ( X+ y)
(2.27)^2 + 2(2.27)(1) + (1)^2 ( 2.27 + 1)
5.15 + 4.54 + 1( 3.27)
5.15+ 4.54 + 3.27
12.96
this is your answer....
hope it helps you ☺..
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